26(169-t^2)=0

Solution for 26(169-t^2)=0 equation:

26(169-t^2)=0

We multiply parentheses

-26t^2+4394=0

a = -26; b = 0; c = +4394;
Δ = b2-4ac
Δ = 02-4·(-26)·4394
Δ = 456976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{456976}=676$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-676}{2*-26}=\frac{-676}{-52}
=+13
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+676}{2*-26}=\frac{676}{-52}
=-13
$